vector function takes vector input ?

9 vues (au cours des 30 derniers jours)
Nora Khaled
Nora Khaled le 10 Fév 2019
Commenté : Star Strider le 13 Fév 2019
Hello !
I am having truble inserting vectors as an input to a function that is a vector
what I did is
I defined a function as
gradient=@(x) [1;x;x^2;x^3];
then I need to input a vector to it. like this
gradient([2 ;3 ; 4])
or
gradient([2 3 4])
so the result I am hoping for is a matrix where each column represent a function (1,x,x^2,x^3)
and each row is the value of the function at each point in the input vector.
so it would be some thing like:
1 2 4 8
1 3 9 27
1 4 16 46
I have done this using loop. but since the data I am dealing with is large this takes so long and I would brefer a method that does it in a vector form.

Réponse acceptée

Star Strider
Star Strider le 10 Fév 2019
First, gradient is a quite useful built-in MATLAB function, so name your function something different.
Second, your function needs some help.
Try this:
myGradient = @(x) [ones(size(x(:))), x(:), x(:).^2, x(:).^3];
Y = myGradient([2 3 4])
I will leave it to you to explore the details of colon operator single-indexing (it forces ‘x’ here to be a column vector), and the necessity to use the ones function.
Y =
1 2 4 8
1 3 9 27
1 4 16 64
  4 commentaires
Nora Khaled
Nora Khaled le 13 Fév 2019
sorry did not know I had a choice of accepting the answer.
And again, Thank you!
Star Strider
Star Strider le 13 Fév 2019
As always, my pleasure.
Thank you!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by