curve fitting with numeric array instead of analytic form for function of x
Afficher commentaires plus anciens
Hello,
Sorry if this is a silly question, but I've been searching through the help documentation and I've been unable to find an answer. Does MATLAB have the ability to do linear least squares fitting of the type y = a*f1(x) + b*f2(x) + ..., where fi(x) are numerically defined functions of the independent variable? I have f1, f2, f3, and f4 defined in vectors as the normalized (to maximum value) results of source signal measurements. I have another set of signal measurements that I want to 'decompose' into a linear sum of the four sources, with amplitudes determined by least squares.
I've found that I can define functions of 'x' and use the matlab function 'fit' with no problem, but I'm unable to write down an analytic functional form for this type of model, so I don't think the curve fitting toolbox will be of much use. Does anyone have any suggestions?
Thanks a lot,
Chris
2 commentaires
Star Strider
le 10 Août 2012
Do your functions f1(x) ... fi(x) produce vectors equal to length(y) (assuming y is a vector and not a matrix), or are they nonlinear functions that have to be evaluated during the parameter estimation process?
Chris
le 10 Août 2012
Réponse acceptée
Plus de réponses (1)
Teja Muppirala
le 10 Août 2012
If I understand you correctly, then I think all you need is the "backslash" operator. Just like this:
x = (0:0.1:10)';
f1 = sin(x);
f2 = exp(x/10);
f3 = 3./(1+x);
y = 3*f1 - 4*f2 + 8*f3 + 1*randn(size(x));
plot(x,y);
estimated_coeffs = [f1 f2 f3]\y
hold on;
plot(x,[f1 f2 f3]*estimated_coeffs,'r');
3 commentaires
Tom Lane
le 10 Août 2012
Teja's example calculated f1-f3 as expressions. I would think you could calculate them by fetching them out of the table, and still carry out the backslash operation that he recommends.
Catégories
En savoir plus sur Get Started with Curve Fitting Toolbox dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!