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Solve numerical equation with Y at both sides

5 vues (au cours des 30 derniers jours)
Ron Nativ
Ron Nativ le 23 Août 2020
Commenté : Star Strider le 24 Août 2020
Hi all,
I have a general equation I would like to solve. However, it contains the dependent variable Y on both sides.
The eqaution is: Y/Y_0 = B * (1 + x*Y/D)^0.5 * (1-x)^alpha
Where x is the independent variable,
and Y_0, B, D and alpha are constants. What would be the most appropriate function in Matlab for this particular problem?
Thanks,
Ron

Réponses (3)

KSSV
KSSV le 23 Août 2020
You can use symbolic package. Something like this:
syms Y_0 Y B x Y D alpha
eqn = Y/Y_0 - B * (1 + x*Y/D)^0.5 * (1-x)^alpha==0 ;
s = solve(eqn,Y)
  1 commentaire
Ron Nativ
Ron Nativ le 24 Août 2020
Thank you KSSV. Is there a big difference between this and using vpasolve?

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Star Strider
Star Strider le 23 Août 2020
A numeric approach:
Y_0 = 3; % Define Constants
B = 5;
D = 7;
alpha = 11;
x = linspace(0, 0.9, 10);
Yfcn = @(Y,x) B * sqrt(1 + x*Y/D) .* (1-x).^alpha - Y/Y_0; % Use Element-Wise Operations
for k = 1:numel(x)
Y(k) = fzero(@(Y)Yfcn(Y,x(k)), 0.1);
end
figure
plot(x, Y)
grid
Note that if ‘x>1’ the result will be complex (regardless of what the other constants are), and the fzero function will fail. Consider using fsolve instead in this event.
  2 commentaires
Ron Nativ
Ron Nativ le 24 Août 2020
Thanks Star Strider. Luckiliy, my x values are always between 0 and 1.
Star Strider
Star Strider le 24 Août 2020
Then this should work!

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Alan Stevens
Alan Stevens le 23 Août 2020
Modifié(e) : Alan Stevens le 23 Août 2020
Your equation can also be expressed as a quadratic in Y
which could be solved using roots (for specified values of x).
You would need to check that the solutions were consistent with the original equation.

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