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Syed Mohiuddin
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Question
how to ues the exponentials and derivatives in bvp4c
I have a coupled non-linear differential equations u''-b1*(t')*(u')+(1+b1*t)*[G1*F1*t+G2*F1*p-F3*P]=0; t''-b2*(t')^2+B*F6*(u...
6 mois il y a | 1 réponse | 0
1
réponseQuestion
graph is the not plotted as desired because of tolerance level
hi, I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)...
6 mois il y a | 1 réponse | 0
1
réponseQuestion
How to get data points from graph
hi, I have graph, i need to prepare a table of the data for x and y terms. How should i get the data points from the enclosed g...
9 mois il y a | 2 réponses | 0
2
réponsesQuestion
Integration using BVP4C
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2...
plus d'un an il y a | 1 réponse | 0
1
réponseQuestion
How can i get a table values from the program
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)/(dy^...
plus d'un an il y a | 1 réponse | 0
0
réponseQuestion
Unable to meet the tolerance without using more than 1666 mesh points.
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)/(dy^...
plus d'un an il y a | 1 réponse | 0
1
réponseQuestion
I am trying to plot the real part and imaginary part graph using bvp4c and I am getting a straight line,
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)/(dy^...
plus d'un an il y a | 1 réponse | 0
0
réponseQuestion
How to get the derivate using bvp4c
I have a coupled non-linear differential equations u''-b1*(t')*(u')+(1+b1*t)*[G1*F1*t+G2*F1*p-F3*P]=0; t''-b2*(t')^2+B*F6*(u')^2...
presque 2 ans il y a | 1 réponse | 0
1
réponseQuestion
Bvp4c Unable to solve the collocation equations -- a singular Jacobian Encountered
I have a coupled non-linear differential equations u''-b1*(t')*(u')+(1+b1*t)*[G1*F1*t+G2*F1*p-F3*P]=0; t''-b2*(t')^2+B*F6*(u')^2...
presque 2 ans il y a | 1 réponse | 0